SSC Combined Graduate Level Examination
General Intelligence and Reasoning
Q.1
Suraj starts from Point A and drives 6 km towards north. He then takes a right turn, drives 5 km, turns right and drives 9 km. He then takes a right turn and drives 11 km. He takes a final right turn, drives 3 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again?
1. 5 km North-West
2. 6 km East
3. 3 km North-East
4. 4 km South-West
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Suraj's Journey - Interactive Direction Tracking
N S W E A (0,0) 🚗 (0,6) 🚗 (5,6) 🚗 (5,-3) 🚗 (-6,-3) 🚗 P (-6,0) 🚗 6 km 5 km 9 km 11 km 3 km 6 km
Complete Solution with Coordinates
1 A(0,0) → North 6km → __
2 Right turn → East 5km → __
3 Right turn → South 9km → __
4 Right turn → West 11km → __
5 Right turn → North 3km → __
📍 Final Answer Calculation:
• Suraj's final position: P(-6, 0)
• Point A is at: (0, 0)
• Distance from P to A: |-6 - 0| = 6 km
• Direction: P is West of A, so return East
✅ Answer: 6 km East
🏆 2 Marks Secured!
Excellent Work! 🎉